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過D作DE垂直AB,AD=BC=4√3cm,A=45°,根據畢氏定理,在直角三角形ADE中,求出DE=2√6cm則面積=AB*DE=48. 連結DB,根據聯系等腰三角形三線合一,可證三角形ABD為等腰三角形,所以DB=4√3cm
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