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因為A、B均為n階可逆矩陣 所以(A*)*=(|A|A^(-1))*= |A|^n-2(A^(-1))*= |A|^n-1(A*)^(-1) =|A|^n-1(|A|A^(-1))^(-1)=|A|^n-1A/ |A|=|A|^n-2·A
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