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由A,B可逆知A^-1+B^-1 = A^-1(A+B)B^-1 由已知A+B可逆,所以A^-1+B^-1可逆(可逆矩陣的乘積仍可逆) 且(A^-1+B^-1)^-1 = [A^-1(A+B)B^-1]^-1 = B(A+B)^-1A
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