Contact us
Choose a category below so we can get back to you as quickly as possible.
證明:∵a,b∈R,且a+b=1,∴b=1-a,∴(a+2)2 ;+(b+2)2−252=a2+b2+4(a+b)-92 ;=2a2-2a+12=2(a−12)2≥0,∴(a+2)2+(b+2)2≥252 ;成立.
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.