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例如f(x)=x²;*sin(1/x)x≠00 x=0f'(0)=lim [f(x)-f(0)]/x=0,當x→0時所以f'(x)= 2xsin(1/x)-cos(1/x)x≠00 x=0由於lim cos(1/x)不存在,所以當x→0時,lim f'(x)極限不存在,囙此f'(0)≠lim f'(x),當x→0時…
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