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limx->0 arcsin2x/sin3x因為分子分母當x->0時都->0所以應用洛必塔法則,即對分子分母分別求導原式=lim->0 1/√(1-sin^2 2x)*(sin2x)' / cos3x *(3x)'=lim->0 2cos2x/√(1-sin^2 2x)/ 3*cos3x=2cos0/√(1-0)/ 3cos0…
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