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(x+4)^1/2 -2= x / [(x+4)^1/2 +2]所以原極限=lim(x趨於0)x / sin3x * 1/[(x+4)^1/2 +2]顯然x趨於0時,sin3x等價於3x所以原極限=lim(x趨於0)x / 3x * 1/[(x+4)^1/2 +2]=1/3 * 1/4= 1/12故極限值為1/12…
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