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第四
根據抛物線方程可求得焦點座標為(0,1)根據抛物線定義可知點p到焦點的距離與到準線的距離相等,∴yp+1=10,求得yp=9,代入抛物線方程求得x=±6∴p點座標是(±6,9)故答案為:(±6,9)
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