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如圖:畫出5*5的正方形網格 AB=2倍根號2 AE=根號10 連接AF、BG 則AF⊥AB ; ; ; ;BG⊥AB 在AF上取點D,使得AD=AE 在BG上取點C,使得BC=AE ABCD就是所求的邊長分別為2倍根號2和根號10的矩形.
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