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設這個數為m,m+132=a^2m+231=b^2a,b都是自然數且b>a兩式想减,得:b^2-a^2=99(b-a)(b+a)=9999=1*99=3*33=9*11b+a>b-a1)b-a=1b+a=99解得:a=49,b=50m=b^2-231=2500-231=22692)b-a=3b+a=33解得:a=15,b=18m=b^2-231=93…
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