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J =∫√(1+sin2x)dx=(1/2)∫√(1+sint)dt,t=2xLet y = 1+sint then dy = costdt =√y√(2-y)dtJ =∫√y * 1/[√y√(2-y)] dy=∫1/√(2-y)dy= -∫d(2-y)/√(2-y)= -√(2-y)+ C= -√[2-(1+sin2x)] + C=…
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