Who can give me 20 English progressive sentences and 20 present progressive verbs? Please! English good help! First grade is enough!

Who can give me 20 English progressive sentences and 20 present progressive verbs? Please! English good help! First grade is enough!

I'm doing my homework.
You're washing your coat.
He's watching TV.
They're waiting for the train.
What's going on there?
She's watering the flower.
I'm playing the piano.
You're having breakfast.
He's working on a project.
They're running.
He's swimming.
She's fishing.
He's talking to her.
We're argueing some problems.
They're drawing pictures.
Are you helping your friends?
The trees are being planted.
He's listening to the radio.
My father is repairing the car.
My mother is closing the door.
I'm doing my homework. You're washing your coat. He's watching TV. They're waiting for the train. What's going on there? She's watering the flower. I'm playing the piano. You're having breakfast. He's working on a project.
Who knows the rules of English verb plus ing
Under what circumstances does the verb add ing?
When does the verb "ing" end?
And when to double write a little dizzy
I hope it's easy to understand
In English, ing is a suffix of a verb (that is, adding the suffix after the verb) and a participle form of a verb in the continuous tense (be + doing)
He is doing his homework
At the same time, some verbs can be changed into noun form by adding the suffix after them
swim→swimming
The rules for verbs to become progressive are as follows:
Verbs end with a single E and remove E; verbs end with EE and directly add ing, such as: agree → agree; see → see
The verb is monosyllabic: it ends with a single vowel and a single consonant, and the consonant is written in double letters
The final consonant is a monosyllabic verb, or a disyllabic verb with a single consonant
A verb ending in Y, adding ing directly
In the present progressive or the past progressive, use the present participle form of the verb, that is, ing form
Change rules: 1. In general, add ing directly
2. At the end of the verb there is a silent e, go to e and add ing
3. Stress closed syllables (in stressed syllables, there is only one vowel followed by a consonant), double write the last consonant and add ing... To expand
In the present progressive or the past progressive, use the present participle form of the verb, that is, ing form
Change rules: 1. In general, add ing directly
2. At the end of the verb there is a silent e, go to e and add ing
3. Stress closed syllables (in stressed syllables, there is only one vowel followed by a consonant), double write the last consonant and put it away
The rules for verbs to become progressive are as follows:
Verbs end with a single E and remove E; verbs end with EE and add ing directly
The verb is monosyllabic: it ends with a single vowel and a single consonant, and the consonant is written in double letters
Verbs are disyllabic or polysyllabic: the last syllable is the stressed syllable, ending with a single vowel + a single consonant, with double consonants and adding ing
A verb ending in Y is expanded directly by adding ing
The rule of progressive tense
Verbs end with a single E and remove E; verbs end with EE and add ing directly
The verb is monosyllabic: it ends with a single vowel and a single consonant, and the consonant is written in double letters
Verbs are disyllabic or polysyllabic: the last syllable is the stressed syllable, ending with a single vowel + a single consonant, with double consonants and adding ing
A verb ending in Y, put it away
How to use English to explain the ing form of verb
The ing form of verb: the - ing form
It can be divided into three parts
The present participle
Gerund: gerund
Given a function y = 2x + 1, when x = 0, the value of function y is______ .
We put x = 0 into a function y = 2x + 1 and get y = 2 × 0 + 1 = 1
Given the function f (x) = x2 + ax + B, if the set a = {x | x = f (x)}, B = {x | x = f [f (x)]}. If a = {- 1,3}, B is represented by enumeration
A={-1,3},
F (x) - x = x ^ 2 + (A-1) x + B = 0 has two roots - 1 and 3
So A-1 = - (- 1 + 3), B = - 1 * 3
a=-1,b=-3
f(f(x))=x
(x^2-x-3)^2-(x^2-x-3)-3=x
[(x^2-2x-3)+x]^2-[(x^2-2x-3)+x]-3=x
(x^2-2x-3)^2+2x*(x^2-2x-3)+x^2-(x^2-2x-3)-x-3=x
(x^2-2x-3)^2+(2x-1)(x^2-2x-3)+(x^2-2x-3)=0
(x^2-2x-3)(x^2-2x-3+2x-1+1)=0
(x+1)(x-3)(x^2-3)=0
B={-1,3,-√3,√3}
Find the set of all real numbers x which satisfy that x belongs to {1,2, X & # 178;}
It's best to have a process
Analysis: all real numbers represented by X & # 178; are actually all non negative numbers, and 1 and 2 are also among them. So the set that meets the condition is
｛y| y≥0｝
Let the function of X be y = cos ^ 2x-2acos + A ^ 2 + A-1
Let y = cos ^ 2x-2acos + A ^ 2 + A-1 be the minimum f (a) of X,
And f (a) = 1 / 2, find the value of A
That's right. That's the root, the square
Let cosx = t
Then y = T ^ 2-2at + A ^ 2 + A-1 (- 1 ≤ t ≤ 1)
This is about the quadratic equation with one variable t, and the axis of symmetry is a
If a ≥ 0. Y, the minimum value is obtained at f (- 1)
That is, 1 + 2A + A ^ 2 + A-1 = 1 / 2
The solution is a = (- 3 + √ 11) / 2
If a ＜ 0. Y, the minimum value is obtained at f (1)
That is ^ 2A + 1 / 2 a = 1-2
The solution is a = (1 - √ 3) / 2
y=2cos²x-1+2acosx+a²+a-1
=2cos²x+2acosx+a²+a-2
=2(cosx+a/2)²+a²/2+a-2
With the opening upward, the axis of symmetry cosx = - A / 2
-1
The function f (x) = x2 + ax + B (a, B ∈ R) is known, and the set a = {x x = f (x)}, B = {x x = f [f (x)]}
The first question is to prove that a ∈ B, which I will. The second question is when a = {1,3}, B is represented by enumeration, and the answer is f [f (x)] = (x2-x-3) 2 - (x2-x-3) - 3 = x, I can't understand it,
When a = {1,3}, then 1 = 1 + A + B, 3 = 9 + 3A + B, the solution is a = - 1, B = - 3, so f (x) = x ^ 2-x-3, so f [f (x)] = (x ^ 2-x-3) ^ 2 - (x ^ 2-x-3) - 3, because B = {x | x = f [f (x)], there is x = f [f (x)], so (x ^ 2-x-3) ^ 2 - (x ^ 2-x-3) - 3 = X
If there is no real element in the solution set of the equation x & # 178; - 2x + 2A = 0, find the value range of real number a
If there is no solution to the equation, then Δ < 0, that is, Δ = B & # 178; - 4ac = 2 & # 178; - 8A = 4-8a < 0
5
So when a ＞ 0.5, there is no real element in the solution set of the equation x & # 178; - 2x + 2A = 0
That is, the discriminant △ = 4-8a1 / 2
There is no real root, that is
4-8a4
a>0.5
4-4*2a1/2
If f (x) = f (x) - 1 / F (x), and x = LG [f (x)], then f (x) is odd or even, increasing or decreasing
x=lg[f(x)]
f(x)=10^x
F(x)=f(x)-1/f(x)=10^x-(10^-x)
F(-x)=(10^-x)-10^x=-F(x)
It is an odd function
Do you know by drawing
F（x）=10^x-(10^-x)
Is the difference between 10 ^ X and (10 ^ - x)
When x is [- ∞, 0], it is a decreasing function
When [x] is an increasing function, + ∞