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∵四邊形ABCD是正方形,△CDE是等邊三角形,∴AD=CD=DE;∠ADE=90°+60°=150°,∴∠AED=(180°-150°)÷2=15°.同理可得∠CEB=15°,∴∠AEB=∠DEC-∠DEA-∠CEB=30°.故答案為:15°,30°.
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