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證明:∵AE‖CF∴∠AED=∠CFB,…(3分)∵DF=BE,∴DF+EF=BE+EF, ;即DE=BF,…(6分)在△ADE和△CBF中,AE=CF∠AED=∠CFBDE=BF,…(9分)∴△ADE≌△CBF(SAS)…(10分).
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