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俊狼獵英團隊為您 延長AE與DC的延長線相交於F, ∵AB‖CD,∴∠BAE=∠F,∠B=∠FCE, ∵BE=CE,∴ΔABE≌ΔFCE,∴AE=EF,AB=CF, ∴AD=AB+CD=CF+CD=DF, ∴DE是等腰三角形DAF底邊AF的中線, ∴DE⊥AE(等腰三角形三線合一).
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