Contact us
Choose a category below so we can get back to you as quickly as possible.
直線AB的方程為 y=1-x 也即x+y=1 故∫L(x+y)ds=∫L 1ds=∫L ds=|AB|=√[(-1-1)^2+(2-0)^2]=2√2
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.