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圓心在直線2X-Y-3=0上,y=2x-3 設圓心為(a,2a-3) (5-a)^2+(2-2a+3)^2=r^2 (3 - a)^2 +(-2-2a+3)^2=r^2 解得,a=2 r^2=10 圓心(2,1) 方程(x—2)^2+(y-1)^2=10
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