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過A作AE⊥BC,設AC=1,所以CE=根號2/2,CQ=根號2/3,所以EQ=根號2/6 因為AE=根號2/2,所以tan∠EAQ=1/3 代入倍角公式tan2α=2tanα/(1-tan^2(α)) 得到tan∠PAQ=3/4
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