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證明:∵△ABC≌△EDC,∴AC=CE,BC=CD,∠ACB=∠ECD,∴∠ACB+∠ACE=∠ECD+∠ACE,即∠BCE=∠ACD,在△BCE和△DCA中,BC=CD∠BCE=∠DCACE=AC,∴△BCE≌△DCA(SAS),∴BE=AD.
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