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過點C作CG‖AB交EF於G ∵AB=AC,∴△ABC為等腰△ ∠B=∠BCA=75º; M是BC中點,易證△BME≌△CMG ∠B=∠CGM=75º; ∠CFG=75-30=45 ∠CGF=180-75=105 ∠CGF>∠CFG CF>CG=BE
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