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∵DE‖AC,EF‖BC,所以四邊形EFCD是平行四邊形.設ED=x,則AC=4+x.∵AD平分∠BAC,由三角形內角平分線定理,得出ABAC=BDDC=154+x又DECA=BDBC.∴xx+4=1519+x解得x=6(x=-10舍去)故答案為6
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