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∫〔1/(1+√t)〕dt =2∫〔√t/(1+√t)〕d(√t) =2∫〔(1+√t-1)/(1+√t)〕d(√t) =2∫d(√t)-2∫〔1/(1+√t)〕d(√t) =2√t-2ln(1+√t)+C
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