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答案:最小值:3/4,最大值:57 設t=1/2^x,那麼f(x)=t^2-t+1 因為x∈[-3,2],所以t∈[1/4,8] 因為f(x)是以1/2為對稱中心開口方向向上的一元二次函數. 所以當t=1/2時,f(x)有最小值為:3/4 當t=8時,f(x)有最大值為:57
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