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2f(x)-f(-x)=lg(x+1).(1) 2f(-x)-f(x)=lg(-x+1).(2) 2×(1)+(2)得3f(x)=2lg(x+1)+lg(-x+1)=lg[(1+x)²;(1-x)] 故f(x)=(1/3)lg[(1+x)²;(1-x)]
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