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因為2f(x)+f(1/x)=2x 將原式中x與1/x互換 得2f(1/x)+f(x)=2/x 於是得關於f(x)的方程組 2f(x)+f(1/x)=2x 2f(1/x)+f(x)=2/x 解得f(x)=4x/3 - 2/3x
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