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設變數x、y滿足約束條件x≥0x+2y≥32x+y≤3,在坐標系中畫出可行域三角形,將z=x-y整理得到y=x-z,要求z=x-y的最小值即是求直線y=x-z的縱截距的最大值,當平移直線x-y=0經過點A(0,3)時,x-y最小,且最小值為:-3,則目標函數z=x-y的最小值為-3.故答案為:-3.
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