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過點a(3,1,-1)和b(1,-1,0),則向量ab=(-2,-2,1).ab×v=(-4,3,-2). 所以平面方程為-4x+3y-2z+D=0,代入點(1,-1,0)得D=7. 故平面方程為-4x+3y-2z+7=0.
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