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∵f(x)為偶函數,∴f(-x)=f(x),∵g(x)為奇函數,∴g(-x)=-g(x),∵f(x)+g(x)=x2+x-2①∴f(-x)+g(-x)=x2-x-2,即f(x)-g(x)=x2-x-2 ;②聯立①②,解得,f(x)=x2-2,g(x)=x.
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