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ax1²;+bx1+c=ax2²;+bx2+c a(x1+x2)(x1-x2)+b(x1-x2)=0 所以a(x1+x2)+b=0 x1+x2=-b/a 所以x=x1+x2 y=a(-b/a)²;+b(-b/a)+c =b²;/a-b²;/a+c =c
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