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F(x)=xf(x)+x^2 F'(x)=f(x)+xf'(x)+2x 又F'(x)=f(x) 所以,f(x)=f(x)+xf'(x)+2x 則有:f'(x)=-2 則:f(x)=-2x+c 又f(0)=1,即:c=1 所以,f(x)=-2x+1,f'(x)=-2
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