Contact us
Choose a category below so we can get back to you as quickly as possible.
由圓的方程得:圓心A(6,0),即OA=6,半徑r=|AB|=2,∵OB為圓A的切線,∴OB⊥AB,在Rt△AOB中,根據畢氏定理得:切線長|OB|=|OA|2−|AB|2=62−22=42.故答案為:42
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.