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∵∠A-∠C=25°,∠B-∠A=10°,∴∠B-∠C=35°①,∠A=25°+∠C,∵∠A+∠B+∠C=180°,∴25°+∠C+∠B+∠C=180°,即2∠C+∠B=155°②,②-①得,3∠C=120°,解得∠C=40°③,把③代入①得,∠B=75°.故答案為:75°.
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