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lim f(1+△x)-f(1)/3△x 由函數導數定義知 f'(x)=lim[f(x+△x)-f(x)]/△x 所以 lim f(1+△x)-f(1)/3△x =(1/3)*lim [f(1+△x)-f(1)]/△x =f'(1)/3
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