If the fraction (4x-13) / (2x ^ 2 + X-6) is obtained by adding two fractions M / (x + 2) and N / (2x-3), then M=______ ,n=_____

If the fraction (4x-13) / (2x ^ 2 + X-6) is obtained by adding two fractions M / (x + 2) and N / (2x-3), then M=______ ,n=_____

m/(x+2)+n/(2x-3)
=[m*(2x-3)+n*(x+2)]/2x^2+x-6
=[(2m+n)*x-(3m-2n)]/2x^2+x-6
=(4x-13)/(2x^2+x-6)
So 4x-13 = (2m + n) * x - (3m-2n)
2m + n = 4,3m-2n = 13
The solution is: M = 3, n = - 2

Elden Ring Premiere

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