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a=1,b=1,c=-1 ∴x12=[-b±√(b²-4ac)]/2a =[-1±√(1+4)]/2 ∴x12=(-1±√5)/2 解 x²+x-1=0 △=b²-4ac=1+4=5 ∴ x=(-1+√5)/2 或x=(-1-√5)/2
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