If x (upper right 3M + n-2) - 2Y (upper right m + N-1 of Y) = 6 is a bivariate linear equation about X and y, find the value of M and n

If x (upper right 3M + n-2) - 2Y (upper right m + N-1 of Y) = 6 is a bivariate linear equation about X and y, find the value of M and n

X ^ (3m + n-2) - 2Y ^ (M + n-1) = 6 is a bivariate linear equation about X and y
So 3M + n-2 = 1 and M + n-1 = 1
So m = 1 / 2, n = 3 / 2

It is known that 2x-3y-z = 0, x + 3y-14z = 0, and Z ≠ 0. To find the value of 4x-5y + Z / x + y + Z, we can use the quadratic equation

2x-3y-z=0 ①
x+3y-14z=0 ②
① + 2, we get 3x-15z = 0, x = 5Z
Substituting into 1, 3Y = 2x-z = 2 * 5z-z = 9z, y = 3Z
Substituting 4x-5y + Z / x + y + Z
We get (4 * 5z-5 * 3Z + Z) / (5Z + 3Z + Z) = 6 / 9 = 2 / 3

It is known that the equation () x-3y = x + 5 is a quadratic equation of two variables about X and y, and the number represented by () is a number
A can't be - 1 B can't be - 3 C can't be 1 D can't be 3

It is known that the equation () x-3y = x + 5 is a bivariate linear equation about X and y, and that (c) cannot be a number represented by 1
If it is 1, then there is no X term, which is a linear equation with one variable