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由等差數列的性質可得:a3+a5=2a4,a7+a13=2a10,代入已知可得3×2a4+2×3a10=24,即a4+a10=4,故數列的前13項之和S13=13(a1+a13)2=13(a4+a10)2=13×42=26故選B
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