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上下同城e^x y=(e^2x-1)/(e^2x+1) =(e^2x+1-2)/(e^2x+1) =1-2/(e^2x+1) だからy'=-2*[-1/(e^2x+1)²]*(e^2x+1)' =4e^2x/(e^2x+1)²
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