如圖,將矩形紙片ABCD沿對角線AC摺疊,使點B落在點E處,求證:EF=DF.

如圖,將矩形紙片ABCD沿對角線AC摺疊,使點B落在點E處,求證:EF=DF.

證明:∵∠EFA=∠DFC,∠B=∠E=90°,AE=CD,∴△AEF≌△CDF;∴EF=DF.