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由直線y=x+3與抛物線y=-x^2+2x+3交於A、B兩點得x+3=-x+2x+3 x-x=0 x=0或x=1當x=0時,y=3;當x=1時,y=4∴交點為A(0,3)和B(1,4)∴B點橫坐標Bx=1∴S△OAB=1/2×OA×Bx=1/2×3×1=3/2
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