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對稱軸x=-1 所以圓心(-1,0) 韋達定理x1+x2=-2 x1x2=m 則AB^2=|x1-x2|^2 =(x1+x2)^2-4x1x2 =4-4m 則r^2=AB^2/4=1-m 所以(x+1)^2+y^2=1-m,其中m
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