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設三角形A(a,0),B(b,0),C(c,y) M((a+b+c)/3,y/3) 向量AM=((b+c-2a)/3,y/3) 向量BM=((a+c-2b)/3,y/3) 向量CM=((a+b-2c)/3,-2y/3) 向量AM+BM+CM=(0,0)=0向量
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