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證明:連接AD,BD 因為DC平分∠ACB 所以∠ACD=∠BCD 所以弧AD=弧BD 所以點D是弧ADB的中點 連接OD,根據垂徑定理 OD⊥AB 因為L是切線 所以OD⊥L 所以AB‖L(同垂直於一條直線的2條直線平行)
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