(1-tanα)/(1+tanα)=3-2√2求[(sinα+cosα)^2-1]/(cotα-sinα乘cosα)的值

(1-tanα)/(1+tanα)=3-2√2求[(sinα+cosα)^2-1]/(cotα-sinα乘cosα)的值

[(sinα+cosα)^2-1]/(cotα-sinα乘cosα)=2sinacosa/(cota-sinacoa)=2/[(csca)^2-1]=2(tana)^2又由(1-tanα)/(1+tanα)=3-2√21-tana=(3-2√2)+(3-2√2)tana即(2√2-4)tana=2-2√2tana=(2-2√2)/(2√2-4)所以原式…