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a⊥b向量a*向量b=0.,f(x)=a*b*x^2+(b^2-a^2)x-a*b 當|向量a|=|向量b|是f(x)=0,不是一次函數所以不充分條件 f(x)=a*b*x^2+(b^2-a^2)x-a*b a*b=0,|向量a|≠|向量b|可知a⊥b所以是必要條件
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