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∵f(x)是定義在R上的奇函數,∴f(-x)=-f(x),∵當x≥0時,f(x)=x2-2x,∴當x<0時,-x>0,f(x)=-f(-x)=-[(-x)2-2(-x)]=-x2-2x,(x<0)故答案為:f(x)=-x2-2x.
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