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因為有兩個相等的實數根,所以Δ=0 Δ=4(b-a)^2-4*(c-b)*(a-b) =4(b-a)*(b-a+c-b) =4(b-a)(c-a) =0 所以 a=b或者c=a 因此 這個三角形是等腰Δ
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