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完全平方,(a+√3b)^2 =a^2+(√3b)^2+2√3ab =a^2+3b^2+2√3ab=7-4√3 由題得a^2+3b^2=7(*),2√3ab=-4√3 就是ab=-2,a=負2分之b,帶入(*),得a=2或a=-2, 當a=2時,b=-1,當a=-2時,b=-1
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