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∵m,n互為相反數,∴m+n=0,∵c,d互為倒數,∴cd=1,∵a到原點的距離為1,∴a=±1,a=1時,3m+3n+2cd+a=3(m+n)+2cd+a=0+2+1=3,a=-1時,3m+3n+2cd+a=3(m+n)+2cd+a=0+2-1=1,所以,3m+3n+2cd+a的值是:3或1.
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