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x^2+2x+y^2-6y+10=0 整理已知式: (x^2-2x+1)+(y^2+6y+9)=0 (x-1)^2+(y+3)^2=0 因為任何數的平方都是非負數,所以此時: x-1與y+3只能同時等於零,才能使(x-1)^2+(y+3)^2=0成立. 即:x=1,y=-3
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